7m^2=16

Solution for 7m^2=16 equation:

7m^2=16

We move all terms to the left:

7m^2-(16)=0

a = 7; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·7·(-16)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{7}}{2*7}=\frac{0-8\sqrt{7}}{14}
=-\frac{8\sqrt{7}}{14}
=-\frac{4\sqrt{7}}{7}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{7}}{2*7}=\frac{0+8\sqrt{7}}{14}
=\frac{8\sqrt{7}}{14}
=\frac{4\sqrt{7}}{7}
$